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受欢迎的三角函数 >

solvefor x,y^2=-2tan(2x)

解答

求解

x, y^{2} = - 2 tan (2 x)

解答

x = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

求解步骤

y^{2} = - 2 tan (2 x)

交换两边

- 2 tan (2 x) = y^{2}

两边除以

- 2

- 2 tan (2 x) = y^{2}

两边除以

- 2

\frac{- 2 tan ( 2 x )}{- 2} = \frac{y ^{2}}{- 2}

化简

tan (2 x) = - \frac{y ^{2}}{2}

tan (2 x) = - \frac{y ^{2}}{2}

使用反三角函数性质

tan (2 x) = - \frac{y ^{2}}{2}

tan (2 x) = - \frac{y ^{2}}{2}

的通解

tan (x) = a \Rightarrow x = arctan (a) + πn

2 x = arctan (- \frac{y ^{2}}{2}) + πn

2 x = arctan (- \frac{y ^{2}}{2}) + πn

解

2 x = arctan (- \frac{y ^{2}}{2}) + πn : x = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

2 x = arctan (- \frac{y ^{2}}{2}) + πn

两边除以

2

2 x = arctan (- \frac{y ^{2}}{2}) + πn

两边除以

2

\frac{2 x}{2} = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

化简

x = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

x = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

x = \frac{arctan ( - \frac{y ^{2}}{2} )}{2} + \frac{πn}{2}

作图

流行的例子

2cos^2(a)-3cos(a)+1=0

2 cos^{2} (a) - 3 cos (a) + 1 = 0

sin(x)*cos(2x)=0.5-sin(2x)*cos(x)

sin (x) \cdot cos (2 x) = 0.5 - sin (2 x) \cdot cos (x)

tan (x) = 0.625

4sin^2(2θ)+6=9

4 sin^{2} (2 θ) + 6 = 9

tan(a)= 1/(sqrt(3))

tan (a) = \frac{1}{3}