27^{2x}=9^{x+1}

Lösung

2 7^{2 x} = 9^{x + 1}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

2 7^{2 x} = 9^{x + 1}

Wende Exponentenregel an

6 x = 2 (x + 1)

Löse

6 x = 2 (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

2^{x} + \frac{1}{2 ^{x}} = 2

9^{- x} = 3^{x + 2}

7^{2 x + 3} = 7^{3 x - 4}

so l v e f or x, x^{y} = e^{x - y}

1 0^{2 x + 6} = 243